2x 3y < X^2 since x^2 will be positive number i divided both sides by X^2 the equation provided became (2x3y)/x^2 Solve the differential equation x^3d^3y/dx^3 3x^2d^2y/dx^2 xdy/dx 8y = 65xos(logx), x > 0 asked in Mathematics by Nakul ( 702k points) differential equations